IBM
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Numerical Ability
Age Problem
A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
A. 14 years B. 18 years
C. 20 years D. 22 years
Read Solution (Total 9)
-
- son=x
man=x+24
after 2 years son=x+2
after 2 years man=x+24+2
x+24+2=2(x+2)
=>x+26=2x+4
=>x=22
ANS=22 - 9 years agoHelpfull: Yes(14) No(1)
- 29
23+6=29 - 12 years agoHelpfull: Yes(6) No(6)
- son =y, father=x
x=y+24 ---- eq(1)
after 2 years son=x+2,father=y+2
=> x+2=2(y+2) ---- eq(2)
solving eq(1) and eq(2)
we get y=22
- 9 years agoHelpfull: Yes(3) No(0)
- 8+1=9
9+2=11
11+3=14
14+4=18
18+5=23
then
23+6=29 - 9 years agoHelpfull: Yes(2) No(5)
- ans is 29. coz the difference is increasing order by 1
- 9 years agoHelpfull: Yes(2) No(2)
- M-S=24 and M- 2S=2 solving both the equations S=22
- 9 years agoHelpfull: Yes(2) No(0)
- diffrence is 1 2 3 4 5 etc
next number=23+6=29 - 9 years agoHelpfull: Yes(1) No(0)
- lets take son age 22 years then father age is 46 years
after 2 years son age 24....father age i s 48
condition satisfied..so choose 22 years as u r answer - 9 years agoHelpfull: Yes(1) No(0)
- A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of his son is:
A. 14 years
B. 18 years
C. 20 years
D. 22 years
Answer: Option D
Explanation:
Let the son's present age be x years. Then, man's present age = (x + 24) years.
(x + 24) + 2 = 2(x + 2)
x + 26 = 2x + 4
x = 22
write answer - 7 years agoHelpfull: Yes(1) No(0)
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