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Mr. and Mrs.Ghosh have some children. Seven of them don’t eat lettuce, five of them don’t eat banana and six of them don’t eat cabbage. Exactly two of them don’t eat cabbage and lettuce, three of them don’t eat banana and cabbage, and four of them don’t eat lettuce and banana. One eats none of these. And there is no child who eats all of these.
How many children are there?
Read Solution (Total 9)
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- P (A U B U C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(A ∩ C) - P(B ∩ C) + P(A ∩ B ∩ C)
i think using this we can find ans as
no of child = 7+5+6-2-3-4+1 = 10
if it is wrong correct me... - 10 years agoHelpfull: Yes(37) No(0)
- ans: 10
=> 7+5+6-2-3-4+1 useing set theory - 10 years agoHelpfull: Yes(10) No(1)
- ans:10
n(A U B U C)=n(A)+n(B)+n(C)-n(A U B)-n(B U C)-n(C U A)+n(A U B U C)
7+5+6-2-3-4+1=10 - 10 years agoHelpfull: Yes(3) No(2)
- 7+5+6-2-3-4+1=10
- 10 years agoHelpfull: Yes(2) No(0)
- P(C U L)= 2, P(B U C)= 3, P(L u B)=4, P(C)= 6, P(B)= 5 ,P(L)= 7
7+5+6-2-3-4+1=10 - 9 years agoHelpfull: Yes(1) No(0)
- A & B & C
P(E)=7
P(B)=5
P(C)=6,P(C U L)=2,P(B U C)=3,P(L U B)=4,P(N)=1
7+5+6-2-3-4+1=10 - 9 years agoHelpfull: Yes(1) No(0)
- ans Is 6
from set theory (7+6+5)-(4+3+2+3*1)=6 - 10 years agoHelpfull: Yes(0) No(4)
- 13 mey b the ans
- 10 years agoHelpfull: Yes(0) No(4)
- answer is 10 please take the combinations and add them
- 9 years agoHelpfull: Yes(0) No(0)
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