main()
{
int a=10,b;
b=(a++)+(a++);
a=(b++)+(b++);
printf("a=%d and b=%d",a,b);
}

Options
1) a=43 b=21
2) a=42 b=21
3) a=43 b=23
4) a=44 b=20

• ans is a=43,b=21
  because b=(a++)+(a++) means a++ is post increment so value of a will remain as 10 for first time t 1hen it will increment by 1 so b=10+11=21
  same as b=21+22=43
• 9 years agoHelpfull: Yes(29) No(7)
• a=43 and b=23
  
• 9 years agoHelpfull: Yes(17) No(3)
• b=(a++)+(a++) means that 10+10 = 20 will assign in B then A will be increase two times ....after incrementing A become 12 but again a will be override by (b++) + (b++) means 20+20 =40 will assign in A. now B will be increment two times and B become 22.
• 9 years agoHelpfull: Yes(17) No(9)
• a=21 and b= 43
• 9 years agoHelpfull: Yes(7) No(11)
• b=11+11=22, a=23+23=46
• 9 years agoHelpfull: Yes(6) No(8)
• b=10+10;
  now a=12,b=20;
  a=20+20;
  a=40 b=22;
• 9 years agoHelpfull: Yes(5) No(1)
• b=23,a=43
  
• 9 years agoHelpfull: Yes(4) No(1)
• It gives ans as a=40,b=22
• 9 years agoHelpfull: Yes(3) No(2)
• a=10
  b=(a++)+(a++);
  =10+11=21 and a=22;
  now
  a=(b++)+(b++);
  =21+22=43 and b=23;
  therefore,a=43 and b=23;
  because it is postfix operator...value inc after using the presennt value of the variable;
• 9 years agoHelpfull: Yes(3) No(0)
• b=20
  a=40
  a++ is incremented in nextline
• 9 years agoHelpfull: Yes(2) No(8)
• b=21
  a=43
  as a++ means ,first the value is used and then gets incremented
• 9 years agoHelpfull: Yes(2) No(4)
• b=(a++)+(a++)=11+11=22
  a=(b++)+(b++)=23+23=46
  sooooo b=22 and a=46
• 9 years agoHelpfull: Yes(2) No(2)
• b=10+11=21
  a=21+22=43
  Ans:-
  a=43,b=21
  
• 9 years agoHelpfull: Yes(2) No(1)
• A=49
  B=23
  
• 9 years agoHelpfull: Yes(2) No(0)
• value of a & b are
  a=40, b=22
  
• 9 years agoHelpfull: Yes(2) No(1)
• b=23 n a=43
• 9 years agoHelpfull: Yes(2) No(0)
• b=(a++)+(a++)
  b=11+12=23
  a=(b++)+(b++)
  a=24+25=49
  
• 9 years agoHelpfull: Yes(1) No(5)
• so guys my bad
  a++ and ++a
  both increment the value of a by one
  but in a++
  it will return the value before increment
  and ++a it will increment the value after increment
  therefore answer is 21 and 43
• 9 years agoHelpfull: Yes(1) No(0)
• b=10+10=20 coz post increment operator(a++) has been used and thus it will increment only after evaluation of the expression thus a=10+1+1=12. Now by overriding a=20+20=40 with the same logic.Now b will become 22.
  final result
  a=40
  b=22
• 9 years agoHelpfull: Yes(1) No(1)
• Guys,try this on ur complr
• 9 years agoHelpfull: Yes(1) No(1)
• b=10+11=21
  a=21+22+43
• 9 years agoHelpfull: Yes(1) No(0)
• a=43 and b=23
• 9 years agoHelpfull: Yes(1) No(0)
• first a + a assigned to b
  so b=20 for now
  and b+ b assigned to a so 20 + 20=40
  so a== 40 ans.
  and now revised b= b++=11
  so b= 11 + 11= 22 ans.
• 9 years agoHelpfull: Yes(1) No(0)
• a=43 and b=21
• 9 years agoHelpfull: Yes(1) No(0)
• b=10+10=20
  than
  a=b+b=20+20=40
  than b=11+11=22
  
  thus
  a=40
  b=22
• 9 years agoHelpfull: Yes(1) No(1)
• b=(a++)+(a++)
  b=11+11=22
  a=(b++)+(b++)-?
  compiler is giving a = 40 ,how?
• 9 years agoHelpfull: Yes(0) No(2)
• Guys,try this on ur compliler.
• 9 years agoHelpfull: Yes(0) No(2)
• a=43 b=21 because (a++)+(a++) means 10+11 i.e 21 and same as next step
  
• 9 years agoHelpfull: Yes(0) No(1)
• Ans. a=40,b=22
  b=10+10=20;
  a=20+20=40;
  after that b increases so
  b=22;
  
• 9 years agoHelpfull: Yes(0) No(0)
• b=(a++)+(a++); a will be incremented after execution so b=10+10, b=20.and next statement also same as first statement i.e a=20+20,so a=40, and b will be incremented two times i.e b=22
  final ans is a=40,b=22
• 9 years agoHelpfull: Yes(0) No(1)
• b=22,a=40;
  given a=10 tnen
  b=(11+11)=22;
  a=23+23=46;
• 9 years agoHelpfull: Yes(0) No(1)
• a=40 b=22
  here
  b=(a++) + (a++)
  both are post increment
  than b=10+10=20
  but memory location 22
  after a=40
  ans a=40,and b=22
• 9 years agoHelpfull: Yes(0) No(1)
• a=21,b=43
  .
  .
• 9 years agoHelpfull: Yes(0) No(2)
• b= 23 ; as b++ also used in statement a=(b++)+(b++);
  b is incremented to 23
  a=21+22=43
• 9 years agoHelpfull: Yes(0) No(0)
• a=40
  b=22
  initailly a was 10 asigned to b with post inc so value increments after adding
  so,value of b=20 when incremented in a assignment it becomes 22
• 9 years agoHelpfull: Yes(0) No(0)
• a=40
  b=21
  a++ is postincrement so b=20
  a=40
  then b incremented to 21
• 9 years agoHelpfull: Yes(0) No(0)
• 10+11=21
  21+22=43
  a=43 b=21
• 9 years agoHelpfull: Yes(0) No(0)
• option a
  int a=10,b;
  b=10+11=21
  a=21+22=43
  
• 8 years agoHelpfull: Yes(0) No(0)
• a=43 and b=23
• 8 years agoHelpfull: Yes(0) No(0)
• a=43 ,b=21 bcz a++ this is post increment so first assign the value then after increase the value
  here b=(a++)+(a++) a=10 then first 10 assign after that increment the value gives 11 this is is update value again a++ take the update value and assign the value 11 so b=10+11 =21
  so same rule use for a=43.
  
• 8 years agoHelpfull: Yes(0) No(0)
• b=(a++)+(a++) means that 10+10 = 20 will assign in B
  then A will be increase two times ....after incrementing A become 12 but again a will be override by (b++) + (b++) means 20+20 =40 will assign in A.
  now B will be increment two times and B become 22.
  
  so final ans A:40 and B:22
• 8 years agoHelpfull: Yes(0) No(0)
• b=10+11=21
  a=21+22=43
• 8 years agoHelpfull: Yes(0) No(1)
• its solution is 1.......
• 8 years agoHelpfull: Yes(0) No(0)
• a=43
  b=21
  b= 10+11
  a=21+22
• 8 years agoHelpfull: Yes(0) No(1)
• ans is 3
  as (a++)+(a++)= (10)+(11) which is 21 so b is now 21 but a at this time is 12......now the next line (b++)+(b++) = (21)+(22) = 43 so a=43 but b is now 23 at this time..
• 8 years agoHelpfull: Yes(0) No(0)
• a=43 b=21
  because b=(a++)+(a++) means a++ is post increment so value of a will remain as 10 for first time then it will increment by 1 so b=10+11=21
  same as b=21+22=43
  
• 8 years agoHelpfull: Yes(0) No(0)
• answer 4
  so a=40,b=20
• 8 years agoHelpfull: Yes(0) No(0)
• a=43, b=23
  because b=(a++) +(a++) which means a++ is post increment so the value of a is 10 in first, then it will incremented with 1 and becomes 11. therefore 10+11=21 and stores in b.
  
  now b=21, so a=(b++)+(b++), which is also post increment, the value of b is 21 in first and 22 in second and then it will incremented to 23. so the sum would be 21+22=43 which will be stored in a.
  the final values of a and b will be 43 and 23 respectively.
• 4 years agoHelpfull: Yes(0) No(1)