IBM
Company
Numerical Ability
Geometry
The dimensions of a certain machine are 48" X 30" X 52". If the size of the machine is increased proportionately until the sum of its dimensions equals 156",what will be the increase in the shortest side?
Read Solution (Total 4)
-
- sum of dimensions now = 48+30+52 = 130'
Increased sum of dimensions = 156'
increased smallest side = 156*30/130 = 36 "
increase in smallest side = 36-30= 6"
- 13 years agoHelpfull: Yes(128) No(8)
- 48+30+52=130, then 156-130=26
the "proportionately" in the shortest side means 30/130*26=6" - 9 years agoHelpfull: Yes(11) No(2)
- Let dimentions increase in proportion of x
48x+30x+52x=156
so, x=1.2
smallest is 30 * 1.2=36
increase is 36-6=30 - 7 years agoHelpfull: Yes(11) No(0)
- sry 36-30=6
- 7 years agoHelpfull: Yes(0) No(0)
IBM Other Question