A can hit the target 3 times in 6 shots. B hit it in 2 times in 6 shots and C can do it 4 times in 6 shots. They fire a volley. What is the probability that at least 2 shots hit?

1) 1/2

2) 1/3

3) 2/3

4) 3/4

5) NOTA

• @RAKESH RAUSHAN-You are right,can be solved as
  Probability of hitting at least two means probability of hitting any two* one miss+ probability of hitting all.
  e.g (A hit*B hit*C miss)+(B hit*C hit*A miss)+(C hit*A hit*B miss) + (A hit*B hit*C hit)
  = 3/6*4/6*4/6+3/6*2/6*2/6+3/6*2/6*4/6+3/6*2/6*4/6
  =1/2
• 10 years agoHelpfull: Yes(23) No(0)
• ans is--1/2.
  probability that they will hit the terget is 3/6, 2/6 , 4/6 respictevely and that of not hitting is 3/6, 4/6 and 2/6 respictevely
  so probability of hitting at least two target will be ...............
  3/6*4/6*4/6+3/6*2/6*2/6+3/6*2/6*4/6+3/6*2/6*4/6=1/2 ans
• 10 years agoHelpfull: Yes(4) No(1)
• 5-----NOTA
• 10 years agoHelpfull: Yes(0) No(5)
• is this really elitmus question?
• 10 years agoHelpfull: Yes(0) No(1)