if a printer A prints 60 words per minute and printer b prints 80 words in one minute printer A starts at 7.47 and printer b at 8.07 wen ll printer b catch up wit printer A.?

• In 20 mins , A will print 60*20 = 1200 words.
  The printer B can fill this gap @ 20 words per min.
  
  Time taken by B to fill gap of 1200 words = 1200/20 = 60 mins.
  
  so at 9.07 , printer B will catch printer A.
• 13 years agoHelpfull: Yes(16) No(6)
• 60*x=80*(x-20)
  60X=80X-1600
  20X=1600
  x=80 mints
  A s time is 7.47+80 mints=9.07
  
• 9 years agoHelpfull: Yes(2) No(0)
• A prints 60 words/minute
  B prints 80words/minute
  it means b print 20 words more than A in per minute
  therefore, if we calculate for 20 minute then A prints 1200 words
  then,
  1200 words prints by B in 20 minute is 1200/20 = 60 minute
  therefore B vil catch A at 9:07
• 10 years agoHelpfull: Yes(1) No(0)
• The gap between time A and time B is 20 minutes therefore
  In 20 mins , A will print 60*20 = 1200 words.
  The printer B can fill this gap @ 20 words per min.
  
  Time is taken by B to fill a gap of 1200 words = 1200/20 = 60 mins.
  
  so at 9.07 , printer B will catch printer A.
• 8 years agoHelpfull: Yes(0) No(0)