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Logical Reasoning
Mathematical Reasoning
In 50 coins 1 is defective (more weight) .in how many weighs can u find the defective coin?
Read Solution (Total 2)
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- In 4 weighings, we can find defective coin.
- 13 years agoHelpfull: Yes(7) No(8)
- 6
Weigh 25 against 25......Weighing 1
The heavier side contains the dud. Discard the other 25.
Put one coin of the heavier set to one side.
Split the remaining 24 into 3 sets of 8. (A, B and C)
Weigh A against B......Weighing 2
If there is a heavier side, discard the other 16 plus the one coin you put to one side.
If there is not, weigh one set against the remaining 8......Weighing 3
If there is still no heavier group the one you put aside must be the dud coin.
If there is a heavier side take those 8 and weigh 4 against 4......Weighing 4
Take the heavier 4 and weigh 2 against 2......Weighing 5
Take the heavier pair and weigh one against one to find the dud......Weighing 6
- 10 years agoHelpfull: Yes(1) No(0)
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