exam Maths Puzzle Numerical Ability

The perimter of a triangle is 46 cm. The triangle is isosceles now, but if its base were lenghtened by 6cm and each leg were shortened by 2 cm, it would be equilaterial. Find the base of the original triangle.

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how do solve this problem

1-2/3y=9/5-y/5+3/5
1)2x-5/(x-2)(x+6)over/divided by x^-2x+1/(x-2)(x+6)=?

2)4ab*b*b*b*b/a+b/6a^b*b*b*b=?