If one man do a job of two boys. If 12 men's and 15 boys can do a work in 25 days working 7.5 hrs a day. How many boys are required along with 21 men's to complete a work twice the first one in 50 days.

• 12 men=24 boys
  so 24+15=39 boys can do it in 25 days..
  now...for 25 days job boys required=39
  for 1 day job boy required=39/25
  for 50 day job boy required=(39/25)*50=78
  already we have 21 men=42 boys...so boys required=78-42=36 boys
  
• 9 years agoHelpfull: Yes(3) No(1)
• 1M=2B
  From first statement 21M +15B = 21*2B+15B=39B
  From second statement let number of boys required be x therefore 21M+xB=(42+x)B
  now applying the basic formula M1*D1*T1/W2=M2*D2*T2/W1
  (39*25*7.5)*2=(42+X)*50*7.5
  
  NOW IS COMING IN NEGATIVE SING...that means no additional boys are required to complete the job
  
  ans: 0
• 10 years agoHelpfull: Yes(2) No(2)