How many numbers can be formed by using digits 0 to 9, as the number should be divisible by 5 and it should be 4 digit one and no repitation is allowed on digits?

• For a number to be divisbly by 5 we have two choices 0 or 5
  
  case 1 : when choice is 0
  _ _ _ 0 first digt can be filled in 9ways , 2nd in 8 ways, 3rd in 7 ways so 9 * 8 *7 = 504
  case 2 : when choice is 5
  _ _ _ 5 first digi can be in 8 ways (since 0 cannot come ) , 2nd in 8 ,3rd in 7 so 8*8*7 = 448
  
  so it can be in 504 + 448 = 952 ways
• 9 years agoHelpfull: Yes(41) No(8)
• 8p3 for 1st 3 digits =336
  2p1 for last digit =2
  result =336*2 =672
• 9 years agoHelpfull: Yes(11) No(12)
• _ _ _ _:4th digit 0 or 5 so , 2P1=2
  3rd digit has 9 ways i.e) 9P1=9
  2nd digit has 8 ways i.e) 8P1=8
  1st digit has 7 ways i.e) 7P1=7
  result=9*8*7*2=1008
• 9 years agoHelpfull: Yes(4) No(3)
• Total numbers can be formed are==> 9*9*8*7
  9*9*8*7-((9*8*7)+(8*8*7))
  
• 9 years agoHelpfull: Yes(3) No(1)
• frds.dont get confused.praveen kumar is absoluetely correct.nice ans praveen..
• 9 years agoHelpfull: Yes(3) No(0)
• 9p3 ie...9*8*7=504
• 9 years agoHelpfull: Yes(1) No(5)
• 630 numbers can be formed
• 9 years agoHelpfull: Yes(0) No(1)
• 4-digits->!@#$
  $ can have oly 2 ways (0 or 5) = 2
  ! can have 8 ways since we have taken off 0 and 5 hence we have 8
  @ can have 7 ways
  # can have 6 ways
  
  Hence we have 8*7*6*2 ways = 672 ways
• 9 years agoHelpfull: Yes(0) No(3)
• ANS : 952
  4 digit number from 1000 to 9999
  4th digit must be 0/5 So 2 possibilities
  If 4th digit is 0
  1st as 9, 2nd has 8 and 3rd digit has 7 possibilities
  If 4th digit is 5
  1st as 8(0 would turn it into 3 digit number), 2nd has 8 and 3rd digit has 7 possibilities
  
  So possibilities = 9*8*7+8*8*7=56*17=840+112=952
  
• 8 years agoHelpfull: Yes(0) No(0)
• unit digit can be 5 or 0 : 2 ways
  rest 3 ways can be filled in 9*8*7
  ans 9*8*7*2=1008
• 8 years agoHelpfull: Yes(0) No(0)