On a particular day, students who visited a canteen ordered either a burger, a pastry or a sandwich. 19 students had a burger, 25 had a pastry, and 27 had a sandwich. 7 students had a burger and a pastry but not a sandwich, 9 had a pastry and sandwich but not a burger, 5 had a burger and sandwich but not a pastry. 3 students had a burger, a pastry and a sandwich.
How many students had only a burger?
How many students had only a pastry?
How many students had only a sandwich?

• n(B)=19 , n(P) =25 , n(S) =27
  n(BUP)= 7 , n(PUS)=9 , n(BUS) =5 and n(BUPUS) =3
  n(only burgers)= n(B) - n(BUS) - n(BUs)- n(BUPUS)
  =19-7-5-3
  =4
  similarly only pasrty = 6
  onlly sandwich =10
• 10 years agoHelpfull: Yes(14) No(0)
• burger=10
  pastry=12
  sandwich=26
• 11 years agoHelpfull: Yes(0) No(11)
• ans is 13.
  27-(9+5)=13
• 10 years agoHelpfull: Yes(0) No(6)
• from formulae A=A-(ab+ac+abc)=19-(7+9+3)=0
  similarly B=10,C=10
  here A=burger,B=pastry,C=sandwitch
• 10 years agoHelpfull: Yes(0) No(2)