5 boys and 5girls sit around a circular table.what is the probability dat 5 boys are sitting together

• First, consider the case of 5 boys sitting together. Let the 5 boys be one group and 5 girls. So total we have 1+5 people sitting. Also the 5 boys themselves can be seated in 5! ways. Since its a circular table, 6 people can sit in (6-1)!x5! = 5! x 5! ways.
  
  Now no. of ways 5 boys and 5 girls can sit = (10-1)! = 9! ways.
  
  So, probability = (5! x 5!) /9!
• 10 years agoHelpfull: Yes(17) No(1)
• total no of ways 5 boys and 5 girls can sit = (10-1)!
  i.e. 9! ways (circular table).
  consider 5 boys in a single group so 5 boys themselves can be seated in 5! ways.
  so now there should be arrangement of 6 people (i.e. 5 girls and 1 group of boys) = (6-1)! = 5!
  
  so probability that 5 boys are sitting together = (5! * 5!) / 9!
• 10 years agoHelpfull: Yes(5) No(1)
• Ans:5!*5!
  Consider 5 boys as 1 set
  Total 5 girls+ 1 set = 6
  In circle 6 can be arranged in 5! Ways
  In 1 set boys can be arranged in 5! Ways
• 10 years agoHelpfull: Yes(2) No(1)
• 6! * 5! is the right answer consider 5boys as 1 and 5girls as it is
  then (5+1)! * 5!
• 10 years agoHelpfull: Yes(2) No(1)
• 5*5!
  5 ways it can be arranged and (n-1)! since it is a circular table.
  
• 10 years agoHelpfull: Yes(1) No(3)
• 5!*5! since 5 boys should sit together, take them as 1 entity those 5 boys can be arranged in 5! ways Now remaining 5 girls and this 1 entity total= 6 . As circular arrangements. (6-1)!
  Hence Total ways= 5!*5!
• 10 years agoHelpfull: Yes(1) No(1)
• 4!x5!.
  First fix girls position then by circular permutations no. of ways to arrange n girls=(n-1)!. Hence 4!.
  In between there are 5 gaps for boys they can be arranged in 5! ways.
  so 4!x5! is the answer.
• 9 years agoHelpfull: Yes(1) No(1)
• 5+1=6!
  b1b2b3b4b5 g1g2g3g4g5
  boys sit together so 1
  nd girls 5
  so 1+5=6!(ans)
  
• 10 years agoHelpfull: Yes(0) No(6)
• 5!*5!
  (n-1)! since it is a circular table
  
• 10 years agoHelpfull: Yes(0) No(2)