exam
Maths Puzzle
Numerical Ability
find the largest two-digit number which is equl to four times the sum of its digits
Read Solution (Total 4)
-
- first check for 99,sum of 9+9=18
and 18*4=72
now we consider 72 is the hiest no.
no sum of 7+2=9*4=36
now consider 36
which satisfied both side 3+6=9*4=36 which is ans simple - 9 years agoHelpfull: Yes(0) No(0)
- first check for 99,sum of 9+9=18
and 18*4=72
now we consider 72 is the hiest no.
no sum of 7+2=9*4=36
now consider 36
which satisfied both side 3+6=9*4=36 which is ans simple - 9 years agoHelpfull: Yes(0) No(0)
- first check for 99,sum of 9+9=18
and 18*4=72
now we consider 72 is the hiest no.
no sum of 7+2=9*4=36
now consider 36
which satisfied both side 3+6=9*4=36 which is ans simple - 9 years agoHelpfull: Yes(0) No(0)
- first check for 99,sum of 9+9=18
and 18*4=72
now we consider 72 is the hiest no.
no sum of 7+2=9*4=36
now consider 36
which satisfied both side 3+6=9*4=36 which is ans simple - 9 years agoHelpfull: Yes(0) No(0)
exam Other Question