Given a line segment AB having ten points on it and another line segment AC having eight points. How many triangles can be formed joining the dots.
a- 960
b-720
c- 780
d- none of the above

• to get a triangle, either we need two points from line AB and one from AC or two points from AC and one from AB.
  Hence we can do this in the following way: 10C2*8C1 + 8C2*10C1 = 640
  So ans is None of these.
• 9 years agoHelpfull: Yes(22) No(0)
• Answer is
  8+10=18 points in all
  total traingles form will be 18C3
  no. of traingles cannot be form is 10C3 and 8C3 as they ar collinear
  so ans is 18C3-10C3-8C3
• 9 years agoHelpfull: Yes(11) No(0)
• 10c1*8c2+8c1*10c2=280+360=640ways.
  So none of this is correct...
• 9 years agoHelpfull: Yes(1) No(0)
• 10c2*8+8c2*10=45*8+28*10=360+280=740 ways
• 9 years agoHelpfull: Yes(0) No(7)
• As AB and AC intersects each other there will be additional 10*8 = 80 triangles. So, total no. of triangles will be 640+80= 720.....
• 8 years agoHelpfull: Yes(0) No(0)