exam Maths Puzzle Numerical Ability

Solve by completing the square

x^2 + 2 = 2x

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exam Other Question

Factor x^-1/3 out of x^1/3 + x^-1/3
I multiplied x^1/3 by x^-1/3 and got x^-1 and then factored out the x^-1/3 and my answer i got was x^-1/3(i/x + 1) is this correct tan^2([pi]/2-[theta])csc^2[theta]+csc^2[theta]=1/sin^4[theta] can you help me verify if this is correct