find greatest 4 digit no when divided by 10,15,22 leaves remainder of 4 ,9,10respectively.........no is written in d form of ABCD ,........find d value of BC?
a.76 b.88 c.95 d.89

• Ans-C) 95.
  Explanation- For divisibility by 10 to leave remainder 4 , unit digit should be 4.
  For divisibility by 15 to leave remainder 9 , unit digit should be 4 or 9.
  For divisibility by 22 to leave remainder 10 , (sum of digits at odd places) - (sum of digit at even places) = 1.
  So let our no be ABC4.
  So (A+C) - (B+4) = 1 (For divisibility by 22 to leave remainder 10).
  Now check by option.
  eg) By option c) (A+5) - (9+4)=1 Here B=9 and C=5 from option. Hence A=9.
  
  So no becomes 9954 which is the greatest 4 digit no.
  
  Check other options also but that will not be the greatest no.
  
• 10 years agoHelpfull: Yes(7) No(0)
• d - 89
  10 |x
  15 |y-4
  22 |z-9
  | 1- 10
  
  z=22+10=32
  y= 15*z+9=15*32=489
  x= 10*y+4=10*489+4=4894
  so value for BC is 89
  
• 10 years agoHelpfull: Yes(7) No(5)
• this is the simple hcf & lcm question
  by the question let N is the digit
  so N=10a+4........(1)
  N=15b+9........(2)
  N=22c+10......(3)
  in euestion 3 put the value of a=1,2,3,4,5........
  so N=32,54,76.....
  this process follow by equ. 1 & 2
  by 2nd N=23,39,54.....
  by 1st N=14,24,34,44,54
  we see 1st common is 54
  so by lcm concept N=54+LCM of (10,15,22)z
  so N=54+330z
  we want highest 4 digit number so put z=20
  N=54+(330*20)
  n=9954
  so answer is c -95
• 10 years agoHelpfull: Yes(2) No(0)
• c)95
  on dividing 10 it gives 4 remender so last digit is 4.
  on dividing with 22 and last digit is 4 so 2nd last digit is 5
  now check for options with greatest 4 digit number 9954 and verify the condition
• 10 years agoHelpfull: Yes(0) No(2)
• Ans-
  Let a = 10b+4 and b = 15c+9 and c = 22d+10
  on solving sec and third eqn
  b = 330d+159
  on solving first and new eqn
  a = 3300d + 1594
  so put d=0,1,2,3,4... to find d ans
  So Ans is 94
• 10 years agoHelpfull: Yes(0) No(1)
• first go through the options first you select highest option and you can dived each number
  
• 10 years agoHelpfull: Yes(0) No(0)