a woman says " my age is my husbands age reversed. if u take the diffrence between my age and my husband's it will be equal to one by eleventh of the sum of our ages. what is my age? "

• Let husband's age be: 10x+y
  Wife's age : 10y+x
  therefore according to question: (10x+y)-(10y+x)= 1/11(10x+y + 10y+x)
  or,(x+y)/(x-y)=9/1
  By componendo-dividendo : x/y=5/4, as x a nd y are single digit, so, x=5 and y=4
  So husband's age is 54 and wife's age is 45
• 10 years agoHelpfull: Yes(24) No(1)
• husband age= xy
  then wife age= yx
  given, x-y=1/11(x+y)
  by solving,
  x=6,y=5 then xy=65 then yx=56
  so, wife age is 56
• 10 years agoHelpfull: Yes(4) No(20)
• ans=45
  54-45=9=(1/11)(54+45)=99/11=9
• 10 years agoHelpfull: Yes(4) No(1)
• 54-45=(1/11)*(45+54)==>9
  W=45
  H=54
• 10 years agoHelpfull: Yes(2) No(0)