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a woman says " my age is my husbands age reversed. if u take the diffrence between my age and my husband's it will be equal to one by eleventh of the sum of our ages. what is my age? "
Read Solution (Total 4)
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- Let husband's age be: 10x+y
Wife's age : 10y+x
therefore according to question: (10x+y)-(10y+x)= 1/11(10x+y + 10y+x)
or,(x+y)/(x-y)=9/1
By componendo-dividendo : x/y=5/4, as x a nd y are single digit, so, x=5 and y=4
So husband's age is 54 and wife's age is 45 - 10 years agoHelpfull: Yes(24) No(1)
- husband age= xy
then wife age= yx
given, x-y=1/11(x+y)
by solving,
x=6,y=5 then xy=65 then yx=56
so, wife age is 56 - 11 years agoHelpfull: Yes(4) No(20)
- ans=45
54-45=9=(1/11)(54+45)=99/11=9 - 10 years agoHelpfull: Yes(4) No(1)
- 54-45=(1/11)*(45+54)==>9
W=45
H=54 - 10 years agoHelpfull: Yes(2) No(0)
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