Peter and paul are 2 friends.Sum of their ages is 35 years.Peter is twice as old as paul was when peter was as old as paul is now.What is the present age of peter?

• upposing Peter’s age is e and Paul’s age is a
  
  We have a + e = 35………………….. (1)
  
  Now when Peter was Paul’s age which means (e - a) years ago
  
  Peter would have been e - (e - a) = a which is Paul’s age now
  
  Paul would have been a - (e - a) = 2a - e
  
  
  We have been given that Peter’s age is twice what Pauls was,
  
  so e = 2(2a - e) = 4a - 2e which gives 3e = 4a………………….. (2)
  
  For ease of use if a + e = 35; then 3a + 3e = 105 = 3a + 4a from (2) above
  
  Thus 7a = 105
  
  a = 15; e = 20
  
  So Peter is 20 years and Paul is 15 years. The sum is 35 years and when Peter was 15
• 14 years agoHelpfull: Yes(31) No(12)
• NOw Peter is 21 and Paul is 14
  
  when peter is 14 ,,paul is 7,that is twice the age of paul
• 14 years agoHelpfull: Yes(12) No(16)
• sorry i dont know
  
• 14 years agoHelpfull: Yes(8) No(7)
• Let x = Peter's present age
  Let y = Paul's present age
  Let z = the number of years ago indicated by the word "when" above.
  x - z = Peter's age z years ago
  y - z = Paul's age z years ago
  
  
  
  >>The sum of their ages is 35 years.>Peter is twice as old as Paul was when Peter was as old as Paul is now.
• 9 years agoHelpfull: Yes(1) No(0)