exam Maths Puzzle Numerical Ability

Please help me :(

2(x-3)=-6

Thank you.

Read Solution (Total 1)

x=0
2(0-3)=-6
so x=0.
10 years agoHelpfull: Yes(0) No(0)

exam Other Question

What is the image of x^2+y^2=1 under the mapping rule (x,y)> (3x+2,3y-5)? I got [1/3(x-2)]^2+[1/3(y+5)]^2=1 ????? Please help me, I am lost.
complete the square and write the equation in standard form. Then give the center and radius of the circle:
x^2+y^2-2x-4y-4=0

Thank you so much