find maximum remainder when 104 n divided by 51 a 32 b 26 c 2 d 16

ans is c .
9 years agoHelpfull: Yes(3) No(5)
Ans is. a)32
9 years agoHelpfull: Yes(3) No(1)
(102 + 2) mod 51 gives remainder 2 and for the same (104)^n mod 51 give (2)^n remainder and till power of 5 its gives remainder in greater term..i.e (2)^5 = 32 bcoz as power exceeds the no will become divisible by 51 ....like 2^5*2 or 2^5*2*2
9 years agoHelpfull: Yes(2) No(2)
factors of 51=3*17
104/3=34 quotient so 3*34=102...,2 as remainder
104/17=6 quotient so17*6=102 ...,2 as remainder
9 years agoHelpfull: Yes(1) No(4)
must be 32. As when we divide 104 from 51 getting 2 as remainder so max multilpe of 2 upto 51 is 32 thats why 32 is ans..
9 years agoHelpfull: Yes(1) No(0)
32 is ans...
9 years agoHelpfull: Yes(1) No(0)
(104)^n %51= (51+53)^n%51= 53^n%51= (51+2)^n%51= 2^n%51.
n should be 5 so gives max rem. as 32...
9 years agoHelpfull: Yes(0) No(0)
a.32
(104)^n/51
=(2)^n/51
so max power of n=5 because 2^5=32,
so a is the right ans
9 years agoHelpfull: Yes(0) No(0)
ans-32

(102+2)^n
remainder=2^n
now for the largest remainder 2^n must be less than 51
power of 2 which is less than 51 is 2^5 i.e
32
9 years agoHelpfull: Yes(0) No(0)

find maximum remainder when (104)^n divided by 51.
a.32 b.26 c.2 d.16