In a two dimensional array X(9,7) with each element occupying 4 bytes of memory with the address of the first element x(1,1) is 3000,find the address of X(8,5) ?

• Base address+byte required{N(i-1)+(j-1)}
  Here Base addres is 3000.
  Byte required is 4.
  N=Number of columns in an array.
  i=row of the array element of the address to be found.
  j=column of the array element of the address to be found.
  Solution;
  3000+4{7(7)+4}=3212
• 6 years agoHelpfull: Yes(0) No(0)