A super fast bus of KSRTC starting from 'Trivandrum' and reaches 'Attingal' in 45 minutes with an average speed of 40 km/hr. If the speed is increased by 10 km/hr how much time it will take to cover the same distance?

(a)34 minutes
(b)36 minutes
(c) 38 minutes
(d)40 minutes

• answer is: 36 minutes
• 12 years agoHelpfull: Yes(6) No(2)
• d=40*45/60
  =30
  then again same distance
  t=30/50*60
  36m
• 11 years agoHelpfull: Yes(5) No(1)
• t=40*45/50=36
• 9 years agoHelpfull: Yes(2) No(0)
• in one hr 40 km are covered.
  In 45 min 30 km will be covered.
  so dist between those places is 30km
  time = dist/new speed
  time=30*60/50=36min
• 9 years agoHelpfull: Yes(1) No(0)
• b) 36 min
  
  d=s*t
  
  s=40 km/hr=40/60km/min
  t=45min
  
  d=(4/6)*45=30km
  
  now increased speed= 50 km/hr=50/60 km/min
  d=30 km
  t=d/s
  = 36 min
• 8 years agoHelpfull: Yes(1) No(0)
• D=ST
  45*40=50*x
  x=45*4050=36min
• 7 years agoHelpfull: Yes(0) No(0)
• given t=45min,s=40kmph initially
  first calculate the DISTANCE BY USING THE FORMULAE
  D=S*T
  D=40*45 => 1800
  NEXT take t=D/S
  1800/50 => 36MINUTES
• 7 years agoHelpfull: Yes(0) No(1)
• D=ST
  45*40=50*x
  x=45*4050=36min
  
  The Best solution
• 6 years agoHelpfull: Yes(0) No(0)
• option B
  time taken to reach destination = 45 mins
  speed = 40 km/h
  distance = 30km
  New speed=50km/h
  time taken is 36 mins.
• 6 years agoHelpfull: Yes(0) No(0)
• 36 mint
  process: si*t1=s2*t2
• 6 years agoHelpfull: Yes(0) No(0)