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A bus started from bus stand at 8.00am, and after 30 minutes staying at destination, it returned back to the bus stand. The destination is 27 miles from the bus stand. The speed of the bus is 18mph. In return journey bus travels with 50% fast speed. At what time it returns to the bus stand?
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- s=d/t so 18=27/t (i.e) t=1.5hr
after 30 min the time is 10.00 am
speed is 50% fast ie 27mph
from this 27=27/t ie t=1 hr
therefore at 11.00 am the bus vil return to bus stand - 11 years agoHelpfull: Yes(0) No(0)
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