IBM
Company
Numerical Ability
Age Problem
The sum of ages of 5 children born at the intervals of 3 years each is 50 years. What is the age of the youngest child?
A. 4 years B. 8 years
C. 10 years D. None of these
Read Solution (Total 6)
-
- youngest child age x;
x+(x+3)+(x+6)+(x+9)+(x+12)=50
5x=20
x=4
- 9 years agoHelpfull: Yes(9) No(0)
- Let age of youngest child be x years
ATQ, x + (x+3) + (x+6) + (x+9) + (x+12) = 50
5x+ 30 = 50
5x = 20
x = 4 years
A. 4 years - 9 years agoHelpfull: Yes(1) No(0)
- plz ..provide the solutiion....tmrw i have a xam...ayshu.530@gmail.com
- 10 years agoHelpfull: Yes(0) No(0)
- 7^x (1 + 7^2) = 7^x * (1+49) = 7^x * 50
thus atleast divisible by 50 - 10 years agoHelpfull: Yes(0) No(1)
- x+(x+3)+(x+6)+(x+9)+(x+12)=50
5x+30=50
x=4 - 9 years agoHelpfull: Yes(0) No(0)
- let age be x
x+(X+3)+(x+6)+(x+9)+(x+12)=50
5x+30=50
x=4 - 9 years agoHelpfull: Yes(0) No(0)
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