There are 100 people in an organization. If 46 people can speak English, 46 Spanish, 58 French, 16 can speak both English and Spanish, 24 can speak both Spanish and French, 26 both English and French and 7 can speak all the languages. How many are there who cannot speak any of the three languages.

• n(SUEUF)=n(E)+n(S)+n(F)-n(E INT S)-n(S INT F)-n(F INT E)+n(E INT S INT F)
  = 46+46+58-16-24-26+7
  =91
  so those who ccant speck any lang. = 100-91=9ans
• 11 years agoHelpfull: Yes(8) No(0)