The cost price of 20 articles is the same as the selling price of x articles. If the profit is 25%, then the value of x is:
A. 15 B. 16
C. 18 D. 25

• ans is:cow
• 11 years agoHelpfull: Yes(5) No(7)
• 20*(100/125)=16
• 9 years agoHelpfull: Yes(4) No(0)
• LET C.P.=20,S.P.=X
  WE KNOW THAT,GAIN=(S.P.-C.P.)/S.P.
  SO AS PER QUESTION, (20-X)/X=25/100=16(ANS)
• 9 years agoHelpfull: Yes(4) No(0)
• a cows and b goats give more milk than x cows and y goats(its a simple logic)
• 10 years agoHelpfull: Yes(2) No(1)
• C.P. of each article b 1.
  C.P. of X article be 1.
  now, S.P. of X articles= rupee 20;
  (20-X)/x *100 = 25;
  2000 - 100X = 25X;
  125X=2000;
  x= 16;
• 9 years agoHelpfull: Yes(2) No(0)
• 125/100*x=20
  x=16
• 9 years agoHelpfull: Yes(1) No(0)
• simple solution for this problem..
  profit =25% so
  25%=1/4
  
  1--->profit
  4--->quantity sold
  
  if
  5 Articles(4+1) = 4 A
  20 Articles = ?
  just do cross multiplication i.e., 20*4/5 = 80/5
  finally we get 16 ans.
• 9 years agoHelpfull: Yes(1) No(0)
• profit%=20-x/20=25%
  i.e x=15
• 9 years agoHelpfull: Yes(0) No(4)
• formula used will be:
  
  %loss or %profit= C.P-S.P/S.P *100
  
  therefore , %profit=25(given)
  
  so, 20-16/16 * 100 = 25%
  
  check values of S.P directly from options
• 9 years agoHelpfull: Yes(0) No(0)
• Explanation:
  Let the Cost Price of one article = Rs. 1
  CP of x articles = Rs. x
  CP of 20 articles = 20
  Selling price of x articles = 20
  
  Profit = 25% [Given]
  
  ⇒(SP−CPCP)=25100=14⇒(20−x)x=14⇒80−4x=x⇒5x=80⇒x=805=16
  ⇒(SP−CPCP)=25100=14⇒(20−x)x=14⇒80−4x=x⇒5x=80⇒x=805=16
  
• 8 years agoHelpfull: Yes(0) No(0)
• http://www.mastguru.com/the-cost-price-of-20-articles-is-the-same-as-the-selling-price-of-x-articles-if-the-profi/836
  
• 8 years agoHelpfull: Yes(0) No(0)
• let CP=100, SP=125
  CP of 20 = SP of x
  => CP/SP = x/20
  => x= (20*100)/125 = 16
• 7 years agoHelpfull: Yes(0) No(0)
• let CP of 1 article be Rs.1
  therefore for x article CP=Rs. x
  SP of article =Rs. 20
  gain=SP-CP=20-x
  25/100=(20-x)/x
  x=16 ans
• 7 years agoHelpfull: Yes(0) No(0)