A fires 8 shots to B's 5 but A kills only once in 6 shots while B kills once in 1 shots. When B has missed 87 times, A has killed ?

• A kills only once in 6 shorts and B kills once in 1 shot
  let:total shots are 100
  when B has missed 87,then B kills 100-87=13
  A kills only once in 6 shots so 13/6=2
  so when B has missed 87 times at that time A has killed 2 only
  
• 13 years agoHelpfull: Yes(3) No(8)
• Let the total number of shots be x. Then,
  Shots fired by A = 8x/13
  Shots fired by B = 5x/13
  Killing shots by A = 1/5 of 8x/13= 8x/65
  Shots missed by B = 1 of 5x/13 = 5x/13
  
  5x/13 = 87 of x = 87*13/5= 226.
  A=8*226/13 = 139.Ans
  
  
  
  
• 8 years agoHelpfull: Yes(2) No(0)
• B missed 87 shots, so totally fired 174 shots, as B kills once in 1 shot which means B kills in every alternate shot.
  for B's 174 shots, A would fire 280 (approx) shots.
  Now A kills once in 6 shots, i.e every 7th shot by A is a killing shot.
  So A kills 40 (Answer)
• 8 years agoHelpfull: Yes(1) No(0)