A man ate 100 bananas in five days, each day eating 6 more than the previous day. How many bananas did he eat on the first day?

• X+(X+6)+(X+12)+(X+18)+(X+24)=100
  TO SOLVE THIS X=8(FIRST DAY ATE)
• 13 years agoHelpfull: Yes(25) No(1)
• intially 1st day=x
  2nd day=6+x
  3rd day=12+x
  4th day=18+x
  5th day=24+x
  as per condition 5 days
  5x+60=100
  x=8
• 13 years agoHelpfull: Yes(9) No(1)
• n/2{2a+(n-1)d}..
  by using this formula we get
  5/2{2a+(5-1)6}=100
  a=8
• 11 years agoHelpfull: Yes(2) No(1)
• let x be the number of bananas he ate on first day
  so,first day =x
  second day=(x+6)
  Third day=(x+6)+6
  Fourth day=(x+6+6)+6
  Fifth day=(x+6+6+6)+6
  so adding above,we get,5x+60=100
  x=8
• 9 years agoHelpfull: Yes(2) No(1)
• this can be written as a A.P series. Sn(sum of the series) =100, n( no of element)=5, d(common difference)=6, a(1st element)
  therefore, Sn= (n/2)*(2a+(n-1)d)
  100=(5/2)*(2a+24)
  100=5a+60
  a=8
• 8 years agoHelpfull: Yes(0) No(0)
• Guys ,,,right ans is
  
  100 banana ---in---------5 days
  
  let first day ate------ a
  
  so,AP is---- a,a+6,a+12....100(last term)
  so formula is--- last term=first term+(number of terms-1)*difference
  100=a+(5-1)*6
  a=76(solution)
• 8 years agoHelpfull: Yes(0) No(0)
• hjkhhkkujhk
• 7 years agoHelpfull: Yes(0) No(0)