log5 (base of 5) of x + 3 (no parentheses) = log5 (base of 5) of (x-20) + 4

• log(x) + 3 = log(x-20) + 4 [considering the logs are of base 5]
  log(x) = log(x-20) + 1
  log(x) = log(x-20) + log(5) [as log(base of 5) of 5 = 1]
  log(x)= log(5x-100 )
  x=5x-100
  x=25
• 10 years agoHelpfull: Yes(0) No(0)