Present population of town is 35,000 having males and females. If The population of males is increased by 6% and if the population of females is increased by 4%, then after 1 year the population becomes 36,700. Find the number males and females ?

• Considering total no of males as x and total no of females
  as y, we get first eqn as x+y=35000.
  Now males are increased by 6% and females by 4%, so we get
  2nd eqn as 1.06x+1.04y=36700.
  Using simultaneous eqn, we get
  No of males=15000
  No of females=20000
• 10 years agoHelpfull: Yes(8) No(0)
• let males be x
  let females be y
  then initially, x+y=35000...........(1)
  when increased,
  x+(6x/100)+y+(4x/100)=36700............(2)
  from (1) and (2),
  (6x/100)+(4x/100)=1700
  10x=170000
  x=17000
  and y= 18000
• 7 years agoHelpfull: Yes(2) No(0)
• 17650 males
  17350 females
• 8 years agoHelpfull: Yes(0) No(1)
• 18180 Female & Male 18520
• 8 years agoHelpfull: Yes(0) No(0)