A lady was out for shopping. She spent half of her money in buying A
and gave 1 dollar to bagger. Further she spent half of her remaining
money and gave 2 dollar to charity. Further she spent half of
remaining money and gave 3 dollars to some children. Now she is been left with 1 dollar. How much money she had in the beginning?

The answer is Rs.42.... Yes, she started off with 42 rupees... Take the unknown amount as x and proceed... When she spent half, then the money becomes x/2 and when she gave 1 rupee to the beggar, The remaining money is (x/2)-1. On simplifying it we get (x-2)/2. When she spent half on lunch the remaining money is (x-2)/4. Like this, continue in the same way and you will find the last expression as (x-34)/8. This expression is equal to 1 because she had only one rupee at the end. And so (x-34)/8=1. On solving it, we get x=42...
10 years agoHelpfull: Yes(3) No(0)
going bottom up,
she has 1 dollar, she gave 3$ to children, all of these was half of what she spent
so, 4X2 = 8

similarly, she gave 2$ to charity and she was having 8$ already
so 8+2 = 10, which was half of what she spent
so 10X2 = 20

at the beginning, she gave 1$ to beggar and half of what she spent on shopping,
20+1 = 21
21X2 = 42 Ans.
7 years agoHelpfull: Yes(1) No(0)
ans is 22 dollar.
let x be the money she had
then 1/2(1/2((x/2)-1)-2)-3)=1
by solving above equation x=22.
11 years agoHelpfull: Yes(0) No(5)
POOJA.M.M -- ANS (42) is Right but your approach to solve this question is wrong. Try to solve it in smart way without doing any calculation.its very easy..
7 years agoHelpfull: Yes(0) No(0)

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