The productivity of a team of programmers is given by the function
P(N) = 4000 √N, where N is the total strength. Find the percentage change in productivity if the strength of the team is increased by 1%.
(a) 0.75%
(b) 0.25%
(c) 0.5%
(d) 1%
(e) 2%

• p(n)=4000 a`s`n
  
  increase in 1%= 1+0.01=1.01
  
  p(1.01n)=4000 a`s`(1.01n)
  
  inc in productivity=[p(1.01n)-p(n)]/p(n)
  
  =0.01
  
  =1%
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