Complete the series 35, 25, 49, 35, 63, 45, ? , 55
1] 87
2] 72
3] 77
4] None of these

• odd positions are,
  7*5 =35
  7*7 =49
  7*9 =63
  7*11=77
  even positions are,
  25, (25+10),(25+20),(25+30) .....
  therefore the series is,
  35, 25, 49, 35, 63, 45, 77, 55
• 9 years agoHelpfull: Yes(7) No(0)
• there are two part of the series one is 35,49,63,andhence next no is 77 because difference between two no is 14
  and second series is 25 ,35,45 ,55
• 9 years agoHelpfull: Yes(1) No(0)
• (35,49,63,77)=7*(5,7,9,11)
  so ans = 77
• 9 years agoHelpfull: Yes(1) No(0)
• option 3 (77) is the answer the first no is added with 14 so u get 49 and 3rd number 49 is added with 14 u get 63 and 63 is added with 14 u got 77 that`s the answer simple.
• 9 years agoHelpfull: Yes(0) No(0)
• answer is 77..
  35+14=49, 49+14=63, 63+14=77.
  thats all
  
• 8 years agoHelpfull: Yes(0) No(0)
• for each number we need add 14 and 10 we get answer,
  so 63+14=77
• 8 years agoHelpfull: Yes(0) No(0)
• 5*7=35
  5*5=25...............(5+2=7)
  7*7=49
  7*5=35...............(7+2=9)
  9*7=63
  9*5=45..................(9+2=11)
  (?)11*7=77
  11*5=55
  
• 8 years agoHelpfull: Yes(0) No(0)
• 35 = 7*5 25=5*5
  49=7*7 35 = 5*7
  63 = 7*9 45 = 5*9
  ?(77) = 7*11 55 = 5*11
• 8 years agoHelpfull: Yes(0) No(0)
• Difference between each pair is increased by 4...
  35-25=10
  49-35=14
  63-45=18
  77-55=22
• 7 years agoHelpfull: Yes(0) No(0)