Find two consecutive intergers such that the sum of 2 times the first interger and 4 times the second interger is 46.

• According to question two consecutive integer
  let x ,x+1
  now
  sum of the 2 times of x and 4 time of x+1 is :
  2x+4(x+1)=46
  2x+4x+4=46
  6x=42
  x=7
  x+1=8
  so ans is:
  7,8
  
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