A face of the clock is divided into three parts. First part hours total is equal to the sum of the second and third part. What is the total of hours in the bigger part?

• Sol) the clock normally has 12 hr
  three parts x,y,z
  x+y+z=12
  x=y+z
  2x=12
  x=6
  so the largest part is 6 hrs
  
• 12 years agoHelpfull: Yes(16) No(4)
• numbers on clock= 1,2,3............12
  sum of these numbers= n(n+1)/2= (12*13)/2= 78
  now, let sum of 1st part =x
  ..................2nd part=y
  .................3rd part= z
  so, x+y+z=78 -----eq1
  let, x= y+z (given) -----eq2
  
  putting value of y+z=x from eq2 in eq1 we get,
  2x=78
  so, x=39
  so, sum of largest part, i.e. x=39 hrs
  
• 10 years agoHelpfull: Yes(3) No(8)
• There are total 12 hrs in the clock.
  let the 3 parts be x,y,z
  x+y+z=12
  Let z be the bigger part
  z=x+y
  z=6
  The biggest part is of 6 hrs
• 6 years agoHelpfull: Yes(1) No(0)
• Three parts are
  1st part : 10,9,8
  2nd part : 11,12,1,2
  3rd part : 3,4,5,6,7
  
  so that we can get the sum values of pieces at AP with the common difference of 1.
  Hence total hours in the bigger part is 25 hrs
  
  Thankz MsMr.Pompita..I got the correct soln from ur idea only..But sorry ur answer is nt rit.They dint say tht remaing two pats sum is equal to the bigger part.so we can,t do in that way.
• 9 years agoHelpfull: Yes(0) No(2)