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If the man walks at the rate of 5 kmph, he misses a train by 7 minutes. However, if he walks at the rate of 6 kmph, he reaches the station 5 minutes before the arrival of the train. Find the distance covered by him to reach the station.
Read Solution (Total 2)
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- Let the distance be x
Difference Between time = 12 min, which is 12/60 in hour which is 1/5
Now x/5-x/6 = 1/5
6x-5x/30 = 1/5
x/30 = 1/5
x = 30/5
x=6 So the required distance = 6 - 9 years agoHelpfull: Yes(0) No(0)
- Time difference 12min .
Speed ratio=5:6
Time ratio=6:5
This correspond to= 12*6:12*5
= 72:60
So distance = 5*72/60=6 - 9 years agoHelpfull: Yes(0) No(0)
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