If a, b and g are the roots of the cubic equation (x - 1) (x2 + x + 3) = 0, then the value of (a3 + b3 + g3 is equal to:

a. -1
b. 9
c. 0
d. 3

• option B
  let a= 1
  b+g= -1
  bg= 3
  b^3+g^3= (b+g)^3 - 3bg(b+g)
  b^3+g^3= 8
  a^3 = 1
  a3+b3+c3= 9
  ans is 9
• 7 years agoHelpfull: Yes(0) No(0)