Two taps A and B can fill a tank in 5 hours and 20 hours respectively. If both the taps are open then due to a leakage, it took 30 minutes more to fill the tank. If the tank is full, how long will it take for the leakage alone to empty the tank ?
A. 8 hrs
B. 9 hrs
C. 18 hrs
D. 36 hrs

• Ans (d) 36 hrs
  2 taps can fill in 4 hrs
  With leak it will take 4 1/2 hrs
  now leak can empty in 1/4-1/(4 (1/2))
  1/4-8/9=1/36. so it an empty tank in 36 hrs
• 10 years agoHelpfull: Yes(3) No(1)
• Two taps A and B can fill a tank in 5 hours and 20 hours respectively. If both the taps are open then due to a leakage, it took 30 minutes more to fill the tank. If the tank is full, how long will it take for the leakage alone to empty the tank ?
  A. 8 hrs
• 8 years agoHelpfull: Yes(2) No(1)
• Part filled by (A + B) in 1 hour = (1/5 + 1/20)
  = 1/4.
  So, A and B together can fill the tank in 4 hours.
  With leak it requires 9/2 (4+1/2) hour to fill,
  So with leak in 1 hour together they fills 2/9 part.
  Work done by the leak in 1 hour = (1/4 - 2/9)
  = 1 / 36.
  Therefore, Leak will empty the tank in 36 hrs.
• 7 years agoHelpfull: Yes(1) No(0)