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Two pipes A and B can separately fill a cistern in 60 minutes and 75 minutes respectively. There is a third pipe in the bottom of the cistern to empty it. If all the three pipes are simultaneously opened, then the cistern is full in 50 minutes. In how much time, the third pipe alone can empty the cistern?
A. 90 min
B. 100 min
C. 110 min
D. 120 min
Read Solution (Total 2)
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- 1/50-(1/60+1/75)=-1/100
third pipe can empty in 100 minutes
a+b+c-(a+b)=c - 8 years agoHelpfull: Yes(0) No(0)
- Let the third pipe empty the cistern in x minutes.
Part of cistern filled in 1 minute when all three pipes are opened simultaneously
=1/60+1/75−1/x
According to the question,
=1/60+1/75−1/x=1/50
⇒1/x=1/60+1/75−1/50
⇒5+4−6/300=3/300
⇒1x=3/300
Therefore x =300/3 = 100 minutes - 5 years agoHelpfull: Yes(0) No(0)
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