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A tank is filled in 5 hours by three pipes A, B and C. The pipe C is twice as fast as B and B is twice as fast as A. How much time will pipe A alone take to fill the tank?

A. 20 hours
B. 25 hours
C. 35 hours
D. Cannot be determined
E. None of these

Read Solution (Total 1)

If c takes x hrs, B takes 2x hrs and A takes 4x hrs,
then
1/x +1/2x = 1/4x = 1/5
7/4x = 1/5
x= 7*5/4 hrs = 35/4 hrs

So A alone will take 4*35/4 = 35 hrs
12 years agoHelpfull: Yes(0) No(1)

GENPACT Other Question

A tank is filled by three pipes with uniform flow. The first two pipes operating simultaneously fill the tank in the same time during which the tank is filled by the third pipe alone. The second pipe fills the tank 5 hours faster than the first pipe and 4 hours slower than the third pipe. The time required by the first pipe is:

A. 6 hours
B. 10 hours
C. 15 hours
D. 30 hours Two pipes A and B together can fill a cistern in 4 hours. Had they been opened separately, then B would have taken 6 hours more than A to fill the cistern. How much time will be taken by A to fill the cistern separately?

A. 1 hour
B. 2 hours
C. 6 hours
D. 8 hours