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Three pipes A, B and C can fill a tank in 6 hours. After working at it together for 2 hours, C is closed and A and B can fill the remaining part in 7 hours. The number of hours taken by C alone to fill the tank is:

A. 10
B. 12
C. 14
D. 16

Read Solution (Total 1)

1/a+1/b+1/c=1/6
after working for 2 hrs. the work done is 1/3. so the remaining work is 2/3.
which is done by a and b in 21 /2 hrs.
1/a+1/b+1/c=1/6
1/a+1/b=2/21
so 1/c-1/6-2/21= 14 hrs.
11 years agoHelpfull: Yes(1) No(1)

GENPACT Other Question

Three taps A, B and C can fill a tank in 12, 15 and 20 hours respectively. If A is open all the time and B and C are open for one hour each alternately, the tank will be full in:

A. 6 hours
B. 20/3hours
C. 7 hours
D. 15/2hours
Two pipes A and B can fill a tank in 36 hours and 45 hours respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the tank?