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Two pipes can fill a tank in 10 hours & 12 hours respectively. While 3rd pipe empties the full tank n 20 hours. If all the three pipes operate simultaneously,in how much time will the tank be filled?
a)6 hrs 43 min
b)2 hrs 25 min
c)7 hrs 30 min
d)6 hrs 32 min
Read Solution (Total 3)
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- tank filled in 1 hr = 1/10 + 1/12 - 1/20 = 8/60 = 2/15 part
so full tank is filled in 15/2 hrs = 7 hr 30 min.. option c) - 12 years agoHelpfull: Yes(0) No(0)
- 1/10+1/12-1/20=8/60
60/8=7.5 - 5 years agoHelpfull: Yes(0) No(0)
- Net part filled in 1 hrs = (1/10+1/12 - 1/20)
Now tack LCM = 6+5-3/60 = 8/60
= 2/15 = 15/2 hrs
Ans = 7:30 min or (7.5) - 3 years agoHelpfull: Yes(0) No(0)
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