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Two pipes A&B can fill a tank in 24 min and 32 min respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is full in 18 min.

a)8 min
b)3 min
c)21 min
d)23 min

Read Solution (Total 3)

3/4 tank is filled by A in 18 mins.
then balance 1/4 tank is filled by B in 32*1/4 = 8 mins......option a)
12 years agoHelpfull: Yes(1) No(0)

The answer that i have is this :

Let B be closed after x minutes Then,
part filled by(A+B) in x min + part filled by A in (18-x) min =1

thus x*(1/24+1/32) + (18-x)*1/24 = 1

7x/96+(18-x)/24 =1

7x+4(18-x)=96

x=8

Hence B is 8 min
8 years agoHelpfull: Yes(1) No(0)
Let B be closed after x minutes Then,
part filled by(A+B) in x min + part filled by A in (18-x) min =1

thus x*(1/24+1/32) + (18-x)*1/24 = 1

7x/96+(18-x)/24 =1

7x+4(18-x)=96

x=8

Hence B is 8 min
8 years agoHelpfull: Yes(0) No(0)

GENPACT Other Question

Bucket P has thrice the capacity as Bucket Q. It takes 60 turns for Bucket P to fill the empty drum. How many turns it will take for both the buckets P&Q, having each turn together to fill the empty drum?

a)45
b)53
c)46
d)63 A tank is filled by 3 pipes with uniform flow. The first two pipes operating simultaneously fill the tan in the same time during which the tank is filled by the third pipe alone. The 2nd pipe fills the tank 5 hours faster than first pipe and 4 hours slower than third pipe. The time required by first pipe is

a)13 hours
b)45 hours
c)15 hours
d)12 hours