exam Maths Puzzle Numerical Ability

A man has twenty coins consisting of dimes and quarters. If the dimes were quarters and the quarters were dimes he would have 90 cents more than he has now. How many dimes and quarters does he have.

.10x+.25y=z
.25x+.10y=z+.90

I am stuck.

Read Solution (Total 0)

exam Other Question

Solve the system by graphing and then get an exact solution by using either substitution or eliminations

2x - y = -1

6x + 3y = 0
if one hand equals 4 inches, find the height in feet of a horse that is 16.2 hands`(1 ft= 12 inches)