Infosys
Company
Numerical Ability
Averages
A car left from a Place A at 8.12 am and reached the Place B, 180 miles distant at 11.57 am. What was its average speed in miles per hour?
a)45
b)70
c)48
d)60
e)50
Read Solution (Total 3)
-
- time taken = 3 hrs 45 min = 3.75 hrs = 15/4 hrs
speed = distance /time = 180/(15/4)= 180*4/15 = 48 mph .... option c) - 13 years agoHelpfull: Yes(11) No(0)
- total distance=180 miles
time=3hrs45 min=15/4hrs
av.speeed=total dis./total time=180/(15/4)=48miles/hr......option c - 10 years agoHelpfull: Yes(4) No(0)
- Time taken = (11.57am-8.12am)= 3.45hrs
distance = 180 miles
average speed = 180%3.45= ~50 - 8 years agoHelpfull: Yes(2) No(0)
Infosys Other Question