the diameter of circular garden is 28 m .a road 1.75m wide runs around it.find the cost of gravelling the road at rs 10 per m2

• radius = 14m
  inner radius of road = 14m
  outer radius = 14+1.75 = 15.75m
  Area of road = outer area - inner area = pi*( 15.75^2 - 14^2 ) = 22/7*29.75*1.75 = 163.625
  so, cost = 10*136.625 = Rs 1636.25 Ans.
• 9 years agoHelpfull: Yes(2) No(1)