Maths Olympiad Exam

Q. For which positive integral values of m, 1/2m^2+15 will be closest to 0.01

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For 1/2m^2+15 will be closest to 0.01
2m^2+15 will be closest to 100.

2m^2=100-15=85
m^2 = 42.5
so m can be 6 or 7
12 years agoHelpfull: Yes(8) No(0)

m will be 6 or 7 so that 1/2m^2+15 will be closest to 0.01.
12 years agoHelpfull: Yes(3) No(1)

Maths Olympiad Other Question

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