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Two goods train each 500 m long are running in opposite directions so parallel tracks.Their speeds are 45 kmph and 30 kmph respectively.Find the time taken by the slower train to pass the driver of the first one
a)12 sec b)24 sec c)48 sec d)60 sec
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- ans=24 sec
only need length of slower train which is L=500m
relative sped (both are opposite direction)
s=45+30=75kmph
75*5/18=125/6 m/s
time =dist/speed
=(500*6)/125=24 sec - 8 years agoHelpfull: Yes(2) No(0)
- Ans is 48 sec
time cross to each other= (500 + 500)/ (45 + 30)*5/18 sec
= 18000/375 sec
48 sec Ans. - 12 years agoHelpfull: Yes(0) No(2)
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