Two trains are moving in opposite direction @ 60 kmph and 90 kmph.Their lengths are 1.10 km and 0.9 km respectively.The time taken by the slower train to cross the faster train in seconds is
a)36 b)45 c)48 d)49

• R.S = (60+90)kmph => (150*5/18)m/sec => (125/3)m/sec
  Distance covered = (1.10 + 0.9) km = (2*1000) = 2000 m.
  Required time = (2000 * 3/125) = 48sec.
• 12 years agoHelpfull: Yes(1) No(0)
• R.S = (60+90)kmph => (150*5/18)m/sec => (125/3)m/sec
  
  
  
• 12 years agoHelpfull: Yes(0) No(0)
• 1.10 km=1100 m and 0.9 km = 900 m
  to convert km/h to m/s multiply with 5/18 to the speed.
  now,
  (1100+900)m=(60+90)*5/18*time
  2000 m= 150*5/18*time
  ( 2000*18)/(150*5)=time
  Hence,
  time= 48 s
• 6 years agoHelpfull: Yes(0) No(0)