If 14141 up to 51 digits divide by 625 then what will be the reminder

remainders for 5 ,25, 125 &625:
for 5, divide last 1 digit
for 25, divide last 2 digits
for 125, divide last 3 digits
for 625, divide last 4 divides
4141%625=391
8 years agoHelpfull: Yes(12) No(1)
when 14141...... will divided by 625 it will two types of remainder i.e 164 and 391.
164 is for even digit i.e 1414 , 141414 , 14141414.
391 is for odd digit i.e 14141,1414141,141414141.
As 51 digit is odd .therefore ans is 391.
8 years agoHelpfull: Yes(4) No(0)
Ans will be 164
9 years agoHelpfull: Yes(2) No(11)
plz tell me how.....
9 years agoHelpfull: Yes(0) No(5)
Correct ans is 244
8 years agoHelpfull: Yes(0) No(1)
ans will be 141 take last three and divid it by 625
8 years agoHelpfull: Yes(0) No(1)
1414141/625= upto 51 digits number ends with one and remainder will be 391
8 years agoHelpfull: Yes(0) No(1)
they can differ in number but max product will be when each fire 1 bottle in every round. and that could return 15*15*15*15.
so option (d) is correct.
8 years agoHelpfull: Yes(0) No(1)
remainders for 5 ,25, 125 &625:
for 5, divide last 1 digit
for 25, divide last 2 digits
for 125, divide last 3 digits
for 625, divide last 4 divides
4141%625=391
8 years agoHelpfull: Yes(0) No(1)
4141%625=391
7 years agoHelpfull: Yes(0) No(0)

If 14141.....up to 51 digits divide by 625 then what will be the reminder ?